8.14.1 Special Characters

Below are the characters that are special to the Bourne shell. You've probably already used some of them. Quoting these characters turns off their special meaning. (Yes, the last three characters are quote marks. You can quote quote marks; more on that later.)

# & * ? [ ] ( ) = | ^ ; < > ` $ " ' \

Space, tab, and newline also have special meaning: as argument separators. A slash ( / ) has special meaning to UNIX itself, but not the shell - so quoting doesn't change the meaning of slashes.

8.14.2 How Quoting Works

Table 8.1 summarizes the rules; you might want to look back at it while you read the examples.

Table 8.1: Bourne Shell Quoting Characters

Quoting Character	Explanation
' xxx '	Disable all special characters in xxx .
" xxx "	Disable all special characters in xxx except $ , ` , and \ .
\ x	Disable special meaning of character x . At end of line, a \ removes the newline character (continues line).

To understand which characters will be quoted, imagine this: the Bourne shell reads what you type at a prompt, or the lines in a shell script, character by character from first to last. (It's actually more complicated than that, but not for the purposes of quoting.)

When the shell reads one of the three quoting characters, it:

• Strips away that quoting character.

• Turns off (disables) special meaning of some or all other character(s) until the end of the quoted section, by the rules in Table 8.1 .

You also need to know how many characters will be quoted. The next few sections have examples to demonstrate those rules. Try typing the examples at a Bourne shell prompt, if you'd like. (Don't use C shell; it's different ( 8.15 ) .) If you need to start a Bourne-type shell, type sh ; use CTRL-d when you're done.

• A backslash ( \ ) turns off special meaning (if any) of the next character. For example, \* is a literal asterisk, not a filename wildcard. So, the first expr ( 45.28 ) command gets the three arguments 79 * 45 and multiplies those two numbers:

  $ 
  
  expr 79 \* 45
  
   3555 $ 
  
  expr 79 * 45
  
   expr: syntax error

  In the second example, without the backslash, the shell expanded * into a list of filenames - which confused expr . (If you want to see what I mean, repeat those two examples using echo ( 8.6 ) instead of expr .)

• A single quote ( ' ) turns off special meaning of all characters until the next single quote is found. So, in the command line below, the words between the two single quotes are quoted. The quotes themselves are removed by the shell. Although this mess is probably not what you want, it's a good demonstration of what quoting does:

  $ 
  
  echo Hey!       What's next?  Mike's #1 friend has $$.
  
   Hey! Whats next?  Mikes

  Let's take a close look at what happened. Spaces outside the quotes are treated as argument separators; the shell ignores the multiple spaces. As article 8.6 explains, echo prints a single space between each argument it gets. Spaces inside the quotes are passed on to echo literally. The question mark ( ? ) is quoted; it's given to echo as is, not used as a wildcard.

  So, echo printed its first argument Hey! and a single space. The second argument to echo is Whats next?  Mikes ; it's all a single argument because the single quotes surrounded the spaces (notice that echo prints the two spaces after the question mark: ?   ). The next argument, #1 , starts with a hash mark, which is a comment character ( 44.2 ) . That means the shell will ignore the rest of the string; it isn't passed to echo .

• Double quotes ( " ) work almost like single quotes. The difference is that double quoting allows the characters $ (dollar sign), ` (backquote), and \ (backslash) to keep their special meanings. That lets you do variable substitution ( 6.8 , 6.1 ) and command substitution ( 9.16 ) inside double quotes - and also to stop that substitution where you need to.

  For now, let's repeat the example above. This time, put double quotes around the single quotes (actually, around the whole string):

  $ 
  
  echo "Hey!       What's next?  Mike's #1 friend has $$."
  
   Hey!       What's next?  Mike's #1 friend has 18437.

  The opening double quote isn't matched until the end of the string. So, all the spaces between the double quotes lose their special meaning - and the shell passes the whole string to echo as one argument. The single quotes also lose their special meaning - because double quotes turn off the special meaning of single quotes! So, the single quotes aren't stripped off as they were in the previous example; echo prints them.

  What else lost its special meaning? The hash mark ( # ) did; notice that the rest of the string was passed to echo this time - because it wasn't "commented out." But the dollar sign ( $ ) didn't lose its meaning; the $$ was expanded into the shell's process ID number ( 38.3 ) (in this shell, 18437 ).

In the previous example, what would happen if you put the $ inside the single quotes? (Single quotes turn off the meaning of $ , remember.) Would the shell still expand $$ to its value? Yes, it would: the single quotes have lost their special meaning, so they don't affect any characters between themselves:

$ 

echo "What's next?  How many $$ did Mike's friend bring?"

 What's next?  How many 18437 did Mike's friend bring?

How can you make both the $$ and the single quotes print literally? The easiest way is with a backslash, which still works inside double quotes:

$ 

echo "What's next?  How many \$\$ did Mike's friend bring?"

 What's next?  How many $$ did Mike's friend bring?

Here's another way to solve the problem. A careful look at this will show a lot about shell quoting:

$ 

echo "What's next?  How many "'$$'" did Mike's friend bring?"

 What's next?  How many $$ did Mike's friend bring?

To read that example, remember that a double quote quotes characters until the next double quote is found. The same is true for single quotes. So, the string What's next?  How many  (including the space at the end) is inside a pair of double quotes. The $$ is inside a pair of single quotes. The rest of the line is inside another pair of double quotes. Both of the double-quoted strings contain a single quote; the double quotes turn off its special meaning and the single quote is printed literally.

8.14.3 Single Quotes Inside Single Quotes?

You can't put single quotes inside single quotes. A single quote turns off all special meaning until the next single quote. Use double quotes and backslashes.

8.14.4 Multiline Quoting

Once you type a single quote or double quote, everything is quoted. The quoting can stretch across many lines. (The C shell doesn't work this way.)

For example, in the short script shown in Figure 8.1 , you might think that the $1 is inside quotes... but it isn't.

Figure 8.1: Matching Quotes

Actually, everything but $1 is in quotes. The gray shaded area shows the quoted parts. So $1 is expanded by the Bourne shell, and not by awk .

Here's another example. Let's store a shell variable ( 6.8 ) with a multiline message, the kind that might be used in a shell program. A shell variable must be stored as a single argument; any argument separators (spaces, etc.) must be quoted. Inside double quotes, $ and ` are interpreted ( before the variable is stored, by the way). The opening double quote isn't closed by the end of the first line; the Bourne shell prints secondary prompts ( 9.13 ) ( > ) until all quotes are closed:

$ 

greeting="Hi, $USER. > The date and time now > are:  `date`."

 $ 

echo "$greeting"

 Hi, jerry. The date and time now are:  Tue Sep  1 13:48:12 EDT 1992. $ 

echo $greeting

 Hi, jerry. The date and time now are: Tue Sep 1 13:48:12 EDT 1992. $

The first echo command line uses double quotes. So, the shell variable is expanded, but the shell doesn't use the spaces and newlines in the variable as argument separators. (Look at the extra spaces after the word are: .) The second echo doesn't use double quotes. The spaces and newlines are treated as argument separators; the shell passes 14 arguments to echo , which prints them with single spaces between.

A backslash has a quirk you should know about. If you use it outside quotes, at the end of a line (just before the newline), the newline will be deleted . Inside single quotes, though, a backslash at the end of a line is copied as is. Here are examples. I've numbered the prompts ( 1$ , 2$ , and so on):

1$ 

echo "a long long long long long long

 > 

line or two"

 a long long long long long long line or two 2$ 

echo a long long long long long long\

 > 

line

 a long long long long long longline 3$ 

echo a long long long long long long \

 > 

line

 a long long long long long long line 4$ 

echo "a long long long long long long\

 > 

line"

 a long long long long long longline 5$ 

echo 'a long long long long long long\

 > 

line'

 a long long long long long long\ line

You've seen an example like example 1 before. The newline is in quotes, so it isn't an argument separator; echo prints it with the rest of the (single two-line) argument. In example 2 , the backslash before the newline tells the shell to delete the newline; the words long and line are passed to echo as one argument. Example 3 is usually what you want when you're typing long lists of command-line arguments: Type a space (an argument separator) before the backslash and newline. In example 4 , the backslash inside the double quotes is ignored (compare to example 1). Inside single quotes, as in example 5 , the backslash has no special meaning; it's passed on to echo .